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54401332124455 = 510880266424891
BaseRepresentation
bin11000101111010010011000…
…00100111001101100100111
321010121201100101001021021121
430113221030010321230213
524112302412010440310
6311411343231354411
714313236503253101
oct1427511404715447
9233551311037247
1054401332124455
1116374525820958
126127414082a07
13244803cb31964
14d610779d0571
1564518444c0da
hex317a4c139b27

54401332124455 has 4 divisors (see below), whose sum is σ = 65281598549352. Its totient is φ = 43521065699560.

The previous prime is 54401332124449. The next prime is 54401332124467. The reversal of 54401332124455 is 55442123310445.

It is a happy number.

54401332124455 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 54401332124455 - 211 = 54401332122407 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5440133212441 + ... + 5440133212450.

It is an arithmetic number, because the mean of its divisors is an integer number (16320399637338).

Almost surely, 254401332124455 is an apocalyptic number.

54401332124455 is a deficient number, since it is larger than the sum of its proper divisors (10880266424897).

54401332124455 is a wasteful number, since it uses less digits than its factorization.

54401332124455 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10880266424896.

The product of its (nonzero) digits is 1152000, while the sum is 43.

The spelling of 54401332124455 in words is "fifty-four trillion, four hundred one billion, three hundred thirty-two million, one hundred twenty-four thousand, four hundred fifty-five".

Divisors: 1 5 10880266424891 54401332124455