Base | Representation |
---|---|
bin | 110011001111010001… |
… | …010001111110100001 |
3 | 12021000020020021002020 |
4 | 303033101101332201 |
5 | 1400133324140340 |
6 | 41135141412053 |
7 | 3655241652066 |
oct | 631721217641 |
9 | 167006207066 |
10 | 55017021345 |
11 | 21372746490 |
12 | a7b510a029 |
13 | 525a2ab000 |
14 | 293cb82c6d |
15 | 167005e9d0 |
hex | ccf451fa1 |
55017021345 has 64 divisors (see below), whose sum is σ = 104029228800. Its totient is φ = 24622840320.
The previous prime is 55017021317. The next prime is 55017021377. The reversal of 55017021345 is 54312071055.
It is not a de Polignac number, because 55017021345 - 212 = 55017017249 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 286621 + ... + 438389.
It is an arithmetic number, because the mean of its divisors is an integer number (1625456700).
Almost surely, 255017021345 is an apocalyptic number.
55017021345 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
55017021345 is a deficient number, since it is larger than the sum of its proper divisors (49012207455).
55017021345 is a wasteful number, since it uses less digits than its factorization.
55017021345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 151827 (or 151801 counting only the distinct ones).
The product of its (nonzero) digits is 21000, while the sum is 33.
The spelling of 55017021345 in words is "fifty-five billion, seventeen million, twenty-one thousand, three hundred forty-five".
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