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550341143055 = 32511172329711381
BaseRepresentation
bin10000000001000101110…
…00110110101000001111
31221121112012221202011100
420000202320312220033
533004044313034210
61100453452354143
754521652350304
oct10004270665017
91847465852140
10550341143055
111a2442256360
128a7b0175953
133cb877924a2
141c8cad970ab
15e4b04125c0
hex8022e36a0f

550341143055 has 384 divisors, whose sum is σ = 1207039242240. Its totient is φ = 228501504000.

The previous prime is 550341142961. The next prime is 550341143063.

550341143055 is a `hidden beast` number, since 5 + 5 + 0 + 341 + 1 + 4 + 305 + 5 = 666.

550341143055 is nontrivially palindromic in base 10.

It is not a de Polignac number, because 550341143055 - 27 = 550341142927 is a prime.

It is a super-3 number, since 3×5503411430553 (a number of 36 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 383 ways as a sum of consecutive naturals, for example, 398508465 + ... + 398509845.

It is an arithmetic number, because the mean of its divisors is an integer number (3143331360).

Almost surely, 2550341143055 is an apocalyptic number.

550341143055 is a gapful number since it is divisible by the number (55) formed by its first and last digit.

550341143055 is an abundant number, since it is smaller than the sum of its proper divisors (656698099185).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

550341143055 is a wasteful number, since it uses less digits than its factorization.

550341143055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1543 (or 1540 counting only the distinct ones).

The product of its (nonzero) digits is 90000, while the sum is 36.

It can be divided in two parts, 550341 and 143055, that added together give a palindrome (693396).

The spelling of 550341143055 in words is "five hundred fifty billion, three hundred forty-one million, one hundred forty-three thousand, fifty-five".