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55041503 = 115003773
BaseRepresentation
bin1101000111110…
…1110111011111
310211120101202012
43101331313133
5103042312003
65243421435
71235562566
oct321756737
9124511665
1055041503
1129084550
121652487b
13b53204a
14744abdd
154c738d8
hex347dddf

55041503 has 4 divisors (see below), whose sum is σ = 60045288. Its totient is φ = 50037720.

The previous prime is 55041491. The next prime is 55041517. The reversal of 55041503 is 30514055.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 55041503 - 26 = 55041439 is a prime.

It is a Duffinian number.

It is a plaindrome in base 16.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (55041593) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2501876 + ... + 2501897.

It is an arithmetic number, because the mean of its divisors is an integer number (15011322).

Almost surely, 255041503 is an apocalyptic number.

55041503 is a deficient number, since it is larger than the sum of its proper divisors (5003785).

55041503 is a wasteful number, since it uses less digits than its factorization.

55041503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5003784.

The product of its (nonzero) digits is 1500, while the sum is 23.

The square root of 55041503 is about 7418.9960911164. The cubic root of 55041503 is about 380.3908789562.

Adding to 55041503 its reverse (30514055), we get a palindrome (85555558).

It can be divided in two parts, 5504 and 1503, that added together give a palindrome (7007).

The spelling of 55041503 in words is "fifty-five million, forty-one thousand, five hundred three".

Divisors: 1 11 5003773 55041503