Base | Representation |
---|---|
bin | 11001001100101101100000… |
… | …10101000100111111110000 |
3 | 21021012100220122112211212211 |
4 | 30212112300111010333300 |
5 | 24230333423314314300 |
6 | 313504023522501504 |
7 | 14446260141313264 |
oct | 1446266025047760 |
9 | 237170818484784 |
10 | 55412331401200 |
11 | 16724268530204 |
12 | 626b345804894 |
13 | 24bc48bb30877 |
14 | d97d84b9a0a4 |
15 | 66160665d4ba |
hex | 3265b0544ff0 |
55412331401200 has 60 divisors (see below), whose sum is σ = 140134869694360. Its totient is φ = 20998357159680.
The previous prime is 55412331401183. The next prime is 55412331401213. The reversal of 55412331401200 is 210413321455.
It is a super-2 number, since 2×554123314012002 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3645540519 + ... + 3645555718.
Almost surely, 255412331401200 is an apocalyptic number.
55412331401200 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
55412331401200 is an abundant number, since it is smaller than the sum of its proper divisors (84722538293160).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
55412331401200 is a wasteful number, since it uses less digits than its factorization.
55412331401200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7291096274 (or 7291096263 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 55412331401200 its reverse (210413321455), we get a palindrome (55622744722655).
The spelling of 55412331401200 in words is "fifty-five trillion, four hundred twelve billion, three hundred thirty-one million, four hundred one thousand, two hundred".
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