Base | Representation |
---|---|
bin | 1000111111110100111101010… |
… | …0001110000001101000000000 |
3 | 10002000201112120111222120122020 |
4 | 2033331033110032001220000 |
5 | 1130441141130014021440 |
6 | 10122315235025041440 |
7 | 250234026311343360 |
oct | 21775172416015000 |
9 | 3060645514876566 |
10 | 633128984517120 |
11 | 173809549137553 |
12 | 5b01477ba86280 |
13 | 21237a65152040 |
14 | b24b86bb9c9a0 |
15 | 4d2e2103103d0 |
hex | 23fd3d4381a00 |
633128984517120 has 640 divisors, whose sum is σ = 2622230626498560. Its totient is φ = 126552557813760.
The previous prime is 633128984517103. The next prime is 633128984517151. The reversal of 633128984517120 is 21715489821336.
It is a tau number, because it is divible by the number of its divisors (640).
It is a super-2 number, since 2×6331289845171202 (a number of 30 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (60).
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 10561266 + ... + 37118705.
It is an arithmetic number, because the mean of its divisors is an integer number (4097235353904).
It is a 1-persistent number, because it is pandigital, but 2⋅633128984517120 = 1266257969034240 is not.
Almost surely, 2633128984517120 is an apocalyptic number.
633128984517120 is a gapful number since it is divisible by the number (60) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 633128984517120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1311115313249280).
633128984517120 is an abundant number, since it is smaller than the sum of its proper divisors (1989101641981440).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
633128984517120 is a wasteful number, since it uses less digits than its factorization.
633128984517120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47680036 (or 47680020 counting only the distinct ones).
The product of its (nonzero) digits is 17418240, while the sum is 60.
The spelling of 633128984517120 in words is "six hundred thirty-three trillion, one hundred twenty-eight billion, nine hundred eighty-four million, five hundred seventeen thousand, one hundred twenty".
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