| Base | Representation |
|---|---|
| bin | 11101001010010011101010… |
| … | …11000110100000000000000 |
| 3 | 22102001100222102121212010000 |
| 4 | 32211021311120310000000 |
| 5 | 31401114200234334000 |
| 6 | 344215000011040000 |
| 7 | 16335636606300000 |
| oct | 1645116530640000 |
| 9 | 272040872555100 |
| 10 | 64125831168000 |
| 11 | 19483680a346a8 |
| 12 | 7238023140000 |
| 13 | 29a2069966544 |
| 14 | 11b99c7600000 |
| 15 | 7630d78ec000 |
| hex | 3a5275634000 |
64125831168000 has 3600 divisors, whose sum is σ = 291065807096064. Its totient is φ = 14020057497600.
The previous prime is 64125831167969. The next prime is 64125831168001. The reversal of 64125831168000 is 86113852146.
64125831168000 is a `hidden beast` number, since 6 + 4 + 1 + 2 + 583 + 1 + 1 + 68 + 0 + 0 + 0 = 666.
It is a tau number, because it is divible by the number of its divisors (3600).
It is a super-3 number, since 3×641258311680003 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Harshad number since it is a multiple of its sum of digits (45).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (64125831168001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 239 ways as a sum of consecutive naturals, for example, 2788079615989 + ... + 2788079616011.
Almost surely, 264125831168000 is an apocalyptic number.
64125831168000 is a gapful number since it is divisible by the number (60) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 64125831168000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (145532903548032).
64125831168000 is an abundant number, since it is smaller than the sum of its proper divisors (226939975928064).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
64125831168000 is an frugal number, since it uses more digits than its factorization.
64125831168000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 113 (or 40 counting only the distinct ones).
The product of its (nonzero) digits is 276480, while the sum is 45.
The spelling of 64125831168000 in words is "sixty-four trillion, one hundred twenty-five billion, eight hundred thirty-one million, one hundred sixty-eight thousand".
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