Base | Representation |
---|---|
bin | 10011010101000101011… |
… | …10010100000100011000 |
3 | 2100111022002211102002122 |
4 | 21222202232110010120 |
5 | 41340142140412100 |
6 | 1225035242520412 |
7 | 65661244316264 |
oct | 11524256240430 |
9 | 2314262742078 |
10 | 664155013400 |
11 | 23673721072a |
12 | a8874206108 |
13 | 4a825171bb8 |
14 | 242068bd0a4 |
15 | 12422265985 |
hex | 9aa2b94118 |
664155013400 has 96 divisors (see below), whose sum is σ = 1560181325040. Its totient is φ = 262910799360.
The previous prime is 664155013391. The next prime is 664155013427. The reversal of 664155013400 is 4310551466.
It is a super-2 number, since 2×6641550134002 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 21662882 + ... + 21693518.
Almost surely, 2664155013400 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 664155013400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (780090662520).
664155013400 is an abundant number, since it is smaller than the sum of its proper divisors (896026311640).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
664155013400 is a wasteful number, since it uses less digits than its factorization.
664155013400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31773 (or 31764 counting only the distinct ones).
The product of its (nonzero) digits is 43200, while the sum is 35.
Adding to 664155013400 its reverse (4310551466), we get a palindrome (668465564866).
The spelling of 664155013400 in words is "six hundred sixty-four billion, one hundred fifty-five million, thirteen thousand, four hundred".
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