Base | Representation |
---|---|
bin | 110001000000000111001… |
… | …0001010010101011111100 |
3 | 212211211120011210001120021 |
4 | 1202000032101102223330 |
5 | 1340320231010243030 |
6 | 22153522305301524 |
7 | 1263366223415215 |
oct | 142001621225374 |
9 | 25754504701507 |
10 | 6734748134140 |
11 | 2167210824584 |
12 | 9092a56348a4 |
13 | 39b1127a6950 |
14 | 193d6bd9a40c |
15 | ba2bd91d97a |
hex | 6200e452afc |
6734748134140 has 48 divisors (see below), whose sum is σ = 15489042680160. Its totient is φ = 2444529173760.
The previous prime is 6734748134119. The next prime is 6734748134161. The reversal of 6734748134140 is 414318474376.
It is an interprime number because it is at equal distance from previous prime (6734748134119) and next prime (6734748134161).
It is a super-2 number, since 2×67347481341402 (a number of 26 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (52).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 219500571 + ... + 219531250.
It is an arithmetic number, because the mean of its divisors is an integer number (322688389170).
Almost surely, 26734748134140 is an apocalyptic number.
It is an amenable number.
6734748134140 is an abundant number, since it is smaller than the sum of its proper divisors (8754294546020).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
6734748134140 is a wasteful number, since it uses less digits than its factorization.
6734748134140 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 439031902 (or 439031900 counting only the distinct ones).
The product of its (nonzero) digits is 5419008, while the sum is 52.
The spelling of 6734748134140 in words is "six trillion, seven hundred thirty-four billion, seven hundred forty-eight million, one hundred thirty-four thousand, one hundred forty".
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