Base | Representation |
---|---|
bin | 100000001100100010… |
… | …0011101111010101101 |
3 | 20121110111020220000000 |
4 | 1000121010131322231 |
5 | 2113044330001003 |
6 | 51432411454513 |
7 | 4665232653111 |
oct | 1003104357255 |
9 | 217414226000 |
10 | 69140078253 |
11 | 2735a854144 |
12 | 11496a57439 |
13 | 669b24430c |
14 | 34bc72d741 |
15 | 1be9d9e1a3 |
hex | 101911dead |
69140078253 has 64 divisors (see below), whose sum is σ = 110472499200. Its totient is φ = 43139152368.
The previous prime is 69140078233. The next prime is 69140078321. The reversal of 69140078253 is 35287004196.
It is not a de Polignac number, because 69140078253 - 213 = 69140070061 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 69140078199 and 69140078208.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (69140078233) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3438876 + ... + 3458922.
It is an arithmetic number, because the mean of its divisors is an integer number (1726132800).
It is a 1-persistent number, because it is pandigital, but 2⋅69140078253 = 138280156506 is not.
Almost surely, 269140078253 is an apocalyptic number.
It is an amenable number.
69140078253 is a deficient number, since it is larger than the sum of its proper divisors (41332420947).
69140078253 is an equidigital number, since it uses as much as digits as its factorization.
69140078253 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20170 (or 20152 counting only the distinct ones).
The product of its (nonzero) digits is 362880, while the sum is 45.
The spelling of 69140078253 in words is "sixty-nine billion, one hundred forty million, seventy-eight thousand, two hundred fifty-three".
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