76320551141 has 2 divisors, whose sum is σ = 76320551142. Its totient is φ = 76320551140.

The previous prime is 76320551129. The next prime is 76320551143. The reversal of 76320551141 is 14115502367.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 48599966116 + 27720585025 = 220454^2 + 166495^2 .

It is an emirp because it is prime and its reverse (14115502367) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-76320551141 is a prime.

It is a super-3 number, since 3×76320551141³ (a number of 34 digits) contains 333 as substring.

Together with 76320551143, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (76320551143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 38160275570 + 38160275571.

It is an arithmetic number, because the mean of its divisors is an integer number (38160275571).

Almost surely, 2^76320551141 is an apocalyptic number.

It is an amenable number.

76320551141 is a deficient number, since it is larger than the sum of its proper divisors (1).

76320551141 is an equidigital number, since it uses as much as digits as its factorization.

76320551141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25200, while the sum is 35.

The spelling of 76320551141 in words is "seventy-six billion, three hundred twenty million, five hundred fifty-one thousand, one hundred forty-one".