81340134134000 has 160 divisors (see below), whose sum is σ = 224787093752832. Its totient is φ = 27886874400000.

The previous prime is 81340134133963. The next prime is 81340134134027. The reversal of 81340134134000 is 43143104318.

It is a super-4 number, since 4×81340134134000⁴ (a number of 57 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 374125325 + ... + 374342675.

Almost surely, 2^{81340134134000} is an apocalyptic number.

81340134134000 is a gapful number since it is divisible by the number (80) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 81340134134000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (112393546876416).

81340134134000 is an abundant number, since it is smaller than the sum of its proper divisors (143446959618832).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

81340134134000 is a wasteful number, since it uses less digits than its factorization.

81340134134000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 244112 (or 244096 counting only the distinct ones).

The product of its (nonzero) digits is 13824, while the sum is 32.

Adding to 81340134134000 its reverse (43143104318), we get a palindrome (81383277238318).

The spelling of 81340134134000 in words is "eighty-one trillion, three hundred forty billion, one hundred thirty-four million, one hundred thirty-four thousand".