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9913304816935 = 513152512381799
BaseRepresentation
bin1001000001000001111100…
…0000110001110100100111
31022002200222020221122021021
42100100133000301310213
52244404422013120220
633030035342232011
72042132635424452
oct220203700616447
938080866848237
109913304816935
1131822331478a3
121141321885607
1356ba88c13c30
14263b41102499
15122d03cbb4aa
hex9041f031d27

9913304816935 has 8 divisors (see below), whose sum is σ = 12811040071200. Its totient is φ = 7320594326304.

The previous prime is 9913304816911. The next prime is 9913304817121. The reversal of 9913304816935 is 5396184033199.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 9913304816935 - 25 = 9913304816903 is a prime.

It is a super-2 number, since 2×99133048169352 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 76256190835 + ... + 76256190964.

It is an arithmetic number, because the mean of its divisors is an integer number (1601380008900).

Almost surely, 29913304816935 is an apocalyptic number.

9913304816935 is a deficient number, since it is larger than the sum of its proper divisors (2897735254265).

9913304816935 is a wasteful number, since it uses less digits than its factorization.

9913304816935 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 152512381817.

The product of its (nonzero) digits is 18895680, while the sum is 61.

The spelling of 9913304816935 in words is "nine trillion, nine hundred thirteen billion, three hundred four million, eight hundred sixteen thousand, nine hundred thirty-five".

Divisors: 1 5 13 65 152512381799 762561908995 1982660963387 9913304816935