Base | Representation |
---|---|
bin | 1001000001111011000010… |
… | …0100011000010111000011 |
3 | 1022011011112102021102010002 |
4 | 2100132300210120113003 |
5 | 2300132314211414120 |
6 | 33041052255430215 |
7 | 2043214515251000 |
oct | 220366044302703 |
9 | 38134472242102 |
10 | 9928631748035 |
11 | 3188788868000 |
12 | 114429a82536b |
13 | 57035c3c9c30 |
14 | 26479690a8a7 |
15 | 1233ee65e375 |
hex | 907b09185c3 |
9928631748035 has 512 divisors, whose sum is σ = 17453540966400. Its totient is φ = 5378788800000.
The previous prime is 9928631748019. The next prime is 9928631748041. The reversal of 9928631748035 is 5308471368299.
It is not a de Polignac number, because 9928631748035 - 24 = 9928631748019 is a prime.
It is a super-2 number, since 2×99286317480352 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (65).
It is an unprimeable number.
It is a polite number, since it can be written in 511 ways as a sum of consecutive naturals, for example, 39556301660 + ... + 39556301910.
It is an arithmetic number, because the mean of its divisors is an integer number (34088947200).
It is a 2-persistent number, because it is pandigital, and so is 2⋅9928631748035 = 19857263496070, but 3⋅9928631748035 = 29785895244105 is not.
Almost surely, 29928631748035 is an apocalyptic number.
9928631748035 is a deficient number, since it is larger than the sum of its proper divisors (7524909218365).
9928631748035 is a wasteful number, since it uses less digits than its factorization.
9928631748035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 397 (or 361 counting only the distinct ones).
The product of its (nonzero) digits is 78382080, while the sum is 65.
The spelling of 9928631748035 in words is "nine trillion, nine hundred twenty-eight billion, six hundred thirty-one million, seven hundred forty-eight thousand, thirty-five".
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