Base | Representation |
---|---|
bin | 11100111001100110110… |
… | …10011000101110010000 |
3 | 10111221002212200121020121 |
4 | 32130303122120232100 |
5 | 112232131000003100 |
6 | 2040102232120024 |
7 | 131512315510642 |
oct | 16346332305620 |
9 | 3457085617217 |
10 | 993000000400 |
11 | 353146681661 |
12 | 140549836014 |
13 | 72840c92b45 |
14 | 360c08ca892 |
15 | 1ac6be4c51a |
hex | e733698b90 |
993000000400 has 60 divisors (see below), whose sum is σ = 2396380844032. Its totient is φ = 395418798720.
The previous prime is 993000000397. The next prime is 993000000439. The reversal of 993000000400 is 4000000399.
993000000400 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 5476944 + ... + 5655343.
Almost surely, 2993000000400 is an apocalyptic number.
It is an amenable number.
993000000400 is an abundant number, since it is smaller than the sum of its proper divisors (1403380843632).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
993000000400 is a wasteful number, since it uses less digits than its factorization.
993000000400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11132528 (or 11132517 counting only the distinct ones).
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 993000000400 its reverse (4000000399), we get a palindrome (997000000799).
The spelling of 993000000400 in words is "nine hundred ninety-three billion, four hundred", and thus it is an aban number.
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