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10011312151 is a prime number
BaseRepresentation
bin10010101001011100…
…01000000000010111
3221211201001100110221
421110232020000113
5131000343442101
64333225055211
7503042514661
oct112456100027
927751040427
1010011312151
114278140aa5
121b34927507
13c3714b359
146ad869531
153d8d94aa1
hex254b88017

10011312151 has 2 divisors, whose sum is σ = 10011312152. Its totient is φ = 10011312150.

The previous prime is 10011312119. The next prime is 10011312247. The reversal of 10011312151 is 15121311001.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10011312151 - 25 = 10011312119 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10011352151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005656075 + 5005656076.

It is an arithmetic number, because the mean of its divisors is an integer number (5005656076).

Almost surely, 210011312151 is an apocalyptic number.

10011312151 is a deficient number, since it is larger than the sum of its proper divisors (1).

10011312151 is an equidigital number, since it uses as much as digits as its factorization.

10011312151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 30, while the sum is 16.

Adding to 10011312151 its reverse (15121311001), we get a palindrome (25132623152).

The spelling of 10011312151 in words is "ten billion, eleven million, three hundred twelve thousand, one hundred fifty-one".