Base | Representation |
---|---|
bin | 1001000110110001101110… |
… | …0111001101010100011111 |
3 | 1022110010210201121201001111 |
4 | 2101230123213031110133 |
5 | 2303014120144424413 |
6 | 33143244121122451 |
7 | 2052226326043024 |
oct | 221543347152437 |
9 | 38403721551044 |
10 | 10012032029983 |
11 | 3210096082255 |
12 | 1158495329427 |
13 | 578190b25ca9 |
14 | 2688290c754b |
15 | 1256813ddd3d |
hex | 91b1b9cd51f |
10012032029983 has 2 divisors, whose sum is σ = 10012032029984. Its totient is φ = 10012032029982.
The previous prime is 10012032029981. The next prime is 10012032030023. The reversal of 10012032029983 is 38992023021001.
It is an a-pointer prime, because the next prime (10012032030023) can be obtained adding 10012032029983 to its sum of digits (40).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10012032029983 - 21 = 10012032029981 is a prime.
Together with 10012032029981, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10012032029981) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006016014991 + 5006016014992.
It is an arithmetic number, because the mean of its divisors is an integer number (5006016014992).
Almost surely, 210012032029983 is an apocalyptic number.
10012032029983 is a deficient number, since it is larger than the sum of its proper divisors (1).
10012032029983 is an equidigital number, since it uses as much as digits as its factorization.
10012032029983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 46656, while the sum is 40.
The spelling of 10012032029983 in words is "ten trillion, twelve billion, thirty-two million, twenty-nine thousand, nine hundred eighty-three".
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