10012056070493 has 2 divisors, whose sum is σ = 10012056070494. Its totient is φ = 10012056070492.

The previous prime is 10012056070411. The next prime is 10012056070531. The reversal of 10012056070493 is 39407065021001.

10012056070493 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an a-pointer prime, because the next prime (10012056070531) can be obtained adding 10012056070493 to its sum of digits (38).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8682374948569 + 1329681121924 = 2946587^2 + 1153118^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10012056070493 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10012056070693) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006028035246 + 5006028035247.

It is an arithmetic number, because the mean of its divisors is an integer number (5006028035247).

Almost surely, 2^{10012056070493} is an apocalyptic number.

It is an amenable number.

10012056070493 is a deficient number, since it is larger than the sum of its proper divisors (1).

10012056070493 is an equidigital number, since it uses as much as digits as its factorization.

10012056070493 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 45360, while the sum is 38.

The spelling of 10012056070493 in words is "ten trillion, twelve billion, fifty-six million, seventy thousand, four hundred ninety-three".