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10012100053 is a prime number
BaseRepresentation
bin10010101001100010…
…01000010111010101
3221211202112101021111
421110301020113111
5131001044200203
64333254015021
7503052306034
oct112461102725
927752471244
1010012100053
114278629a5a
121b35047471
13c37365b77
146ad9d271b
153d8e9d26d
hex254c485d5

10012100053 has 2 divisors, whose sum is σ = 10012100054. Its totient is φ = 10012100052.

The previous prime is 10012100051. The next prime is 10012100057. The reversal of 10012100053 is 35000121001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5552932324 + 4459167729 = 74518^2 + 66777^2 .

It is an emirp because it is prime and its reverse (35000121001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10012100053 - 21 = 10012100051 is a prime.

Together with 10012100051, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10012100051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006050026 + 5006050027.

It is an arithmetic number, because the mean of its divisors is an integer number (5006050027).

Almost surely, 210012100053 is an apocalyptic number.

It is an amenable number.

10012100053 is a deficient number, since it is larger than the sum of its proper divisors (1).

10012100053 is an equidigital number, since it uses as much as digits as its factorization.

10012100053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 30, while the sum is 13.

Adding to 10012100053 its reverse (35000121001), we get a palindrome (45012221054).

The spelling of 10012100053 in words is "ten billion, twelve million, one hundred thousand, fifty-three".