Base | Representation |
---|---|
bin | 1001000110110001111111… |
… | …0010001100110001111111 |
3 | 1022110010222121022120121121 |
4 | 2101230133302030301333 |
5 | 2303014241104121343 |
6 | 33143255101211411 |
7 | 2052231135666142 |
oct | 221543762146177 |
9 | 38403877276547 |
10 | 10012102020223 |
11 | 3210121636a26 |
12 | 11584b4860b67 |
13 | 5781a2490234 |
14 | 268834506059 |
15 | 125687616aed |
hex | 91b1fc8cc7f |
10012102020223 has 2 divisors, whose sum is σ = 10012102020224. Its totient is φ = 10012102020222.
The previous prime is 10012102020197. The next prime is 10012102020227. The reversal of 10012102020223 is 32202020121001.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10012102020223 - 25 = 10012102020191 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10012102020197 and 10012102020206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10012102020227) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006051010111 + 5006051010112.
It is an arithmetic number, because the mean of its divisors is an integer number (5006051010112).
Almost surely, 210012102020223 is an apocalyptic number.
10012102020223 is a deficient number, since it is larger than the sum of its proper divisors (1).
10012102020223 is an equidigital number, since it uses as much as digits as its factorization.
10012102020223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 16.
Adding to 10012102020223 its reverse (32202020121001), we get a palindrome (42214122141224).
The spelling of 10012102020223 in words is "ten trillion, twelve billion, one hundred two million, twenty thousand, two hundred twenty-three".
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