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10012102020223 is a prime number
BaseRepresentation
bin1001000110110001111111…
…0010001100110001111111
31022110010222121022120121121
42101230133302030301333
52303014241104121343
633143255101211411
72052231135666142
oct221543762146177
938403877276547
1010012102020223
113210121636a26
1211584b4860b67
135781a2490234
14268834506059
15125687616aed
hex91b1fc8cc7f

10012102020223 has 2 divisors, whose sum is σ = 10012102020224. Its totient is φ = 10012102020222.

The previous prime is 10012102020197. The next prime is 10012102020227. The reversal of 10012102020223 is 32202020121001.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10012102020223 - 25 = 10012102020191 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10012102020197 and 10012102020206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10012102020227) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006051010111 + 5006051010112.

It is an arithmetic number, because the mean of its divisors is an integer number (5006051010112).

Almost surely, 210012102020223 is an apocalyptic number.

10012102020223 is a deficient number, since it is larger than the sum of its proper divisors (1).

10012102020223 is an equidigital number, since it uses as much as digits as its factorization.

10012102020223 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 16.

Adding to 10012102020223 its reverse (32202020121001), we get a palindrome (42214122141224).

The spelling of 10012102020223 in words is "ten trillion, twelve billion, one hundred two million, twenty thousand, two hundred twenty-three".