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10013251212149 is a prime number
BaseRepresentation
bin1001000110110110010001…
…0010000001001101110101
31022110020221200201120120112
42101231210102001031311
52303024114302242044
633144005112312405
72052301461653003
oct221554422011565
938406850646515
1010013251212149
11321066129a919
1211587756a2705
135783265a5563
14268902daba73
1512570346809e
hex91b64481375

10013251212149 has 2 divisors, whose sum is σ = 10013251212150. Its totient is φ = 10013251212148.

The previous prime is 10013251212023. The next prime is 10013251212191. The reversal of 10013251212149 is 94121215231001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7462283231524 + 2550967980625 = 2731718^2 + 1597175^2 .

It is a cyclic number.

It is not a de Polignac number, because 10013251212149 - 224 = 10013234434933 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10013251212949) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006625606074 + 5006625606075.

It is an arithmetic number, because the mean of its divisors is an integer number (5006625606075).

Almost surely, 210013251212149 is an apocalyptic number.

It is an amenable number.

10013251212149 is a deficient number, since it is larger than the sum of its proper divisors (1).

10013251212149 is an equidigital number, since it uses as much as digits as its factorization.

10013251212149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 32.

The spelling of 10013251212149 in words is "ten trillion, thirteen billion, two hundred fifty-one million, two hundred twelve thousand, one hundred forty-nine".