Base | Representation |
---|---|
bin | 11101001010101001000… |
… | …01110110011110100011 |
3 | 10112210201020122011001121 |
4 | 32211110201312132203 |
5 | 112404343224240003 |
6 | 2044213532513111 |
7 | 132255046353466 |
oct | 16452441663643 |
9 | 3483636564047 |
10 | 1002145540003 |
11 | 35700a038953 |
12 | 14228061b797 |
13 | 7366a93ca3a |
14 | 3670b3892dd |
15 | 1b104cc6cbd |
hex | e9548767a3 |
1002145540003 has 2 divisors, whose sum is σ = 1002145540004. Its totient is φ = 1002145540002.
The previous prime is 1002145540001. The next prime is 1002145540021. The reversal of 1002145540003 is 3000455412001.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1002145540003 - 21 = 1002145540001 is a prime.
Together with 1002145540001, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 1002145540003.
It is not a weakly prime, because it can be changed into another prime (1002145540001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501072770001 + 501072770002.
It is an arithmetic number, because the mean of its divisors is an integer number (501072770002).
Almost surely, 21002145540003 is an apocalyptic number.
1002145540003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1002145540003 is an equidigital number, since it uses as much as digits as its factorization.
1002145540003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2400, while the sum is 25.
The spelling of 1002145540003 in words is "one trillion, two billion, one hundred forty-five million, five hundred forty thousand, three".
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