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100240224433 is a prime number
BaseRepresentation
bin101110101011011001…
…0000111000010110001
3100120201220200000012221
41131112302013002301
53120242444140213
6114014423521041
710146021564166
oct1352662070261
9316656600187
10100240224433
1139569aa2298
12175162b9181
1395b650b78b
144bccd1406d
15291a38c38d
hex1756c870b1

100240224433 has 2 divisors, whose sum is σ = 100240224434. Its totient is φ = 100240224432.

The previous prime is 100240224431. The next prime is 100240224463. The reversal of 100240224433 is 334422042001.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 98355622689 + 1884601744 = 313617^2 + 43412^2 .

It is a cyclic number.

It is not a de Polignac number, because 100240224433 - 21 = 100240224431 is a prime.

It is a super-3 number, since 3×1002402244333 (a number of 34 digits) contains 333 as substring.

Together with 100240224431, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 100240224398 and 100240224407.

It is not a weakly prime, because it can be changed into another prime (100240224431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50120112216 + 50120112217.

It is an arithmetic number, because the mean of its divisors is an integer number (50120112217).

Almost surely, 2100240224433 is an apocalyptic number.

It is an amenable number.

100240224433 is a deficient number, since it is larger than the sum of its proper divisors (1).

100240224433 is an equidigital number, since it uses as much as digits as its factorization.

100240224433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4608, while the sum is 25.

Adding to 100240224433 its reverse (334422042001), we get a palindrome (434662266434).

The spelling of 100240224433 in words is "one hundred billion, two hundred forty million, two hundred twenty-four thousand, four hundred thirty-three".