Base | Representation |
---|---|
bin | 111011101111111… |
… | …001010110010101 |
3 | 2120212012202221122 |
4 | 323233321112111 |
5 | 4023104131123 |
6 | 243245053325 |
7 | 33561233153 |
oct | 7357712625 |
9 | 2525182848 |
10 | 1002411413 |
11 | 474920593 |
12 | 23b857245 |
13 | 12c8a2963 |
14 | 971b83d3 |
15 | 5d00abc8 |
hex | 3bbf9595 |
1002411413 has 2 divisors, whose sum is σ = 1002411414. Its totient is φ = 1002411412.
The previous prime is 1002411407. The next prime is 1002411433. The reversal of 1002411413 is 3141142001.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 504541444 + 497869969 = 22462^2 + 22313^2 .
It is an emirp because it is prime and its reverse (3141142001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1002411413 - 26 = 1002411349 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1002411391 and 1002411400.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1002411433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501205706 + 501205707.
It is an arithmetic number, because the mean of its divisors is an integer number (501205707).
Almost surely, 21002411413 is an apocalyptic number.
It is an amenable number.
1002411413 is a deficient number, since it is larger than the sum of its proper divisors (1).
1002411413 is an equidigital number, since it uses as much as digits as its factorization.
1002411413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 17.
The square root of 1002411413 is about 31660.8814311920. The cubic root of 1002411413 is about 1000.8031590961.
Adding to 1002411413 its reverse (3141142001), we get a palindrome (4143553414).
The spelling of 1002411413 in words is "one billion, two million, four hundred eleven thousand, four hundred thirteen".
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