Base | Representation |
---|---|
bin | 10010101011000000… |
… | …00011100011001101 |
3 | 221212121200100010212 |
4 | 21111200003203031 |
5 | 131012221313401 |
6 | 4334413412205 |
7 | 503262001121 |
oct | 112540034315 |
9 | 27777610125 |
10 | 10024401101 |
11 | 4284570a10 |
12 | 1b3919a065 |
13 | c39a81bb0 |
14 | 6b14b5581 |
15 | 3da0ccdbb |
hex | 2558038cd |
10024401101 has 48 divisors (see below), whose sum is σ = 12803638848. Its totient is φ = 7731763200.
The previous prime is 10024401031. The next prime is 10024401113. The reversal of 10024401101 is 10110442001.
It is a de Polignac number, because none of the positive numbers 2k-10024401101 is a prime.
It is a super-3 number, since 3×100244011013 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10024401131) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1774241 + ... + 1779881.
It is an arithmetic number, because the mean of its divisors is an integer number (266742476).
Almost surely, 210024401101 is an apocalyptic number.
10024401101 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
10024401101 is a deficient number, since it is larger than the sum of its proper divisors (2779237747).
10024401101 is a wasteful number, since it uses less digits than its factorization.
10024401101 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5742 (or 5725 counting only the distinct ones).
The product of its (nonzero) digits is 32, while the sum is 14.
Adding to 10024401101 its reverse (10110442001), we get a palindrome (20134843102).
The spelling of 10024401101 in words is "ten billion, twenty-four million, four hundred one thousand, one hundred one".
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