Base | Representation |
---|---|
bin | 11101001100110010110… |
… | …10000101010100000000 |
3 | 10112220200210002021121102 |
4 | 32212121122011110000 |
5 | 112414230042202040 |
6 | 2044524333113532 |
7 | 132325510623122 |
oct | 16463132052400 |
9 | 3486623067542 |
10 | 1003301131520 |
11 | 357552372966 |
12 | 1425436288a8 |
13 | 737c3185bbc |
14 | 367baa39212 |
15 | 1b17148e515 |
hex | e999685500 |
1003301131520 has 144 divisors (see below), whose sum is σ = 2442672977472. Its totient is φ = 394773872640.
The previous prime is 1003301131507. The next prime is 1003301131529. The reversal of 1003301131520 is 251311033001.
It is a super-2 number, since 2×10033011315202 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a junction number, because it is equal to n+sod(n) for n = 1003301131492 and 1003301131501.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1003301131529) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 24733655 + ... + 24774185.
It is an arithmetic number, because the mean of its divisors is an integer number (16963006788).
Almost surely, 21003301131520 is an apocalyptic number.
1003301131520 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1003301131520, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1221336488736).
1003301131520 is an abundant number, since it is smaller than the sum of its proper divisors (1439371845952).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1003301131520 is an equidigital number, since it uses as much as digits as its factorization.
1003301131520 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40868 (or 40854 counting only the distinct ones).
The product of its (nonzero) digits is 270, while the sum is 20.
Adding to 1003301131520 its reverse (251311033001), we get a palindrome (1254612164521).
The spelling of 1003301131520 in words is "one trillion, three billion, three hundred one million, one hundred thirty-one thousand, five hundred twenty".
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