Base | Representation |
---|---|
bin | 101110101110001000… |
… | …0111110110001101111 |
3 | 100120222022202000020221 |
4 | 1131130100332301233 |
5 | 3120440020444434 |
6 | 114031511152211 |
7 | 10151216440501 |
oct | 1353420766157 |
9 | 316868660227 |
10 | 100332203119 |
11 | 39606a05235 |
12 | 17541075667 |
13 | 95cc5a4235 |
14 | 4bdb217d71 |
15 | 29234aa2b4 |
hex | 175c43ec6f |
100332203119 has 2 divisors, whose sum is σ = 100332203120. Its totient is φ = 100332203118.
The previous prime is 100332203057. The next prime is 100332203141. The reversal of 100332203119 is 911302233001.
It is a strong prime.
It is an emirp because it is prime and its reverse (911302233001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 100332203119 - 229 = 99795332207 is a prime.
It is a super-2 number, since 2×1003322031192 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 100332203093 and 100332203102.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100332203519) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50166101559 + 50166101560.
It is an arithmetic number, because the mean of its divisors is an integer number (50166101560).
Almost surely, 2100332203119 is an apocalyptic number.
100332203119 is a deficient number, since it is larger than the sum of its proper divisors (1).
100332203119 is an equidigital number, since it uses as much as digits as its factorization.
100332203119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 25.
The spelling of 100332203119 in words is "one hundred billion, three hundred thirty-two million, two hundred three thousand, one hundred nineteen".
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