1004142114133 has 2 divisors, whose sum is σ = 1004142114134. Its totient is φ = 1004142114132.

The previous prime is 1004142114097. The next prime is 1004142114169. The reversal of 1004142114133 is 3314112414001.

It is a balanced prime because it is at equal distance from previous prime (1004142114097) and next prime (1004142114169).

It can be written as a sum of positive squares in only one way, i.e., 879830868049 + 124311246084 = 937993^2 + 352578^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1004142114133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1004142114098 and 1004142114107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1004142114733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 502071057066 + 502071057067.

It is an arithmetic number, because the mean of its divisors is an integer number (502071057067).

Almost surely, 2^{1004142114133} is an apocalyptic number.

It is an amenable number.

1004142114133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1004142114133 is an equidigital number, since it uses as much as digits as its factorization.

1004142114133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1004142114133 its reverse (3314112414001), we get a palindrome (4318254528134).

The spelling of 1004142114133 in words is "one trillion, four billion, one hundred forty-two million, one hundred fourteen thousand, one hundred thirty-three".