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100649888081 is a prime number
BaseRepresentation
bin101110110111100110…
…0110110100101010001
3100121210110112002002122
41131233030312211101
53122112332404311
6114123220224025
710162124634641
oct1355714664521
9317713462078
10100649888081
113975a268696
121760b53b015
1396503547c2
144c2b4b2521
15294130e0db
hex176f336951

100649888081 has 2 divisors, whose sum is σ = 100649888082. Its totient is φ = 100649888080.

The previous prime is 100649888077. The next prime is 100649888083. The reversal of 100649888081 is 180888946001.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 65290470400 + 35359417681 = 255520^2 + 188041^2 .

It is a cyclic number.

It is not a de Polignac number, because 100649888081 - 22 = 100649888077 is a prime.

It is a super-2 number, since 2×1006498880812 (a number of 23 digits) contains 22 as substring.

Together with 100649888083, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (100649888083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50324944040 + 50324944041.

It is an arithmetic number, because the mean of its divisors is an integer number (50324944041).

Almost surely, 2100649888081 is an apocalyptic number.

It is an amenable number.

100649888081 is a deficient number, since it is larger than the sum of its proper divisors (1).

100649888081 is an equidigital number, since it uses as much as digits as its factorization.

100649888081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 884736, while the sum is 53.

The spelling of 100649888081 in words is "one hundred billion, six hundred forty-nine million, eight hundred eighty-eight thousand, eighty-one".