10102534351541 has 2 divisors, whose sum is σ = 10102534351542. Its totient is φ = 10102534351540.

The previous prime is 10102534351531. The next prime is 10102534351543. The reversal of 10102534351541 is 14515343520101.

It is a happy number.

10102534351541 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5067581774641 + 5034952576900 = 2251129^2 + 2243870^2 .

It is a cyclic number.

It is not a de Polignac number, because 10102534351541 - 2⁶ = 10102534351477 is a prime.

It is a super-2 number, since 2×10102534351541² (a number of 27 digits) contains 22 as substring.

Together with 10102534351543, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10102534351543) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5051267175770 + 5051267175771.

It is an arithmetic number, because the mean of its divisors is an integer number (5051267175771).

Almost surely, 2^{10102534351541} is an apocalyptic number.

It is an amenable number.

10102534351541 is a deficient number, since it is larger than the sum of its proper divisors (1).

10102534351541 is an equidigital number, since it uses as much as digits as its factorization.

10102534351541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36000, while the sum is 35.

Adding to 10102534351541 its reverse (14515343520101), we get a palindrome (24617877871642).

The spelling of 10102534351541 in words is "ten trillion, one hundred two billion, five hundred thirty-four million, three hundred fifty-one thousand, five hundred forty-one".