101044141300 has 72 divisors (see below), whose sum is σ = 231726731040. Its totient is φ = 38137680000.

The previous prime is 101044141273. The next prime is 101044141321. The reversal of 101044141300 is 3141440101.

It is a Harshad number since it is a multiple of its sum of digits (19).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 370962 + ... + 582838.

It is an arithmetic number, because the mean of its divisors is an integer number (3218426820).

Almost surely, 2^101044141300 is an apocalyptic number.

101044141300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 101044141300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (115863365520).

101044141300 is an abundant number, since it is smaller than the sum of its proper divisors (130682589740).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

101044141300 is a wasteful number, since it uses less digits than its factorization.

101044141300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 212161 (or 212154 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 101044141300 its reverse (3141440101), we get a palindrome (104185581401).

The spelling of 101044141300 in words is "one hundred one billion, forty-four million, one hundred forty-one thousand, three hundred".