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101053131541 is a prime number
BaseRepresentation
bin101111000011100111…
…1000110101100010101
3100122211120021222010121
41132013033012230111
53123424100202131
6114231223151541
710205122305565
oct1360717065425
9318746258117
10101053131541
113994694944a
12177025a55b1
1396b5a604bb
144c68c7cda5
152966913911
hex17873c6b15

101053131541 has 2 divisors, whose sum is σ = 101053131542. Its totient is φ = 101053131540.

The previous prime is 101053131539. The next prime is 101053131601. The reversal of 101053131541 is 145131350101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 99234450225 + 1818681316 = 315015^2 + 42646^2 .

It is an emirp because it is prime and its reverse (145131350101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101053131541 - 21 = 101053131539 is a prime.

Together with 101053131539, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101053132541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50526565770 + 50526565771.

It is an arithmetic number, because the mean of its divisors is an integer number (50526565771).

Almost surely, 2101053131541 is an apocalyptic number.

It is an amenable number.

101053131541 is a deficient number, since it is larger than the sum of its proper divisors (1).

101053131541 is an equidigital number, since it uses as much as digits as its factorization.

101053131541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 900, while the sum is 25.

Adding to 101053131541 its reverse (145131350101), we get a palindrome (246184481642).

The spelling of 101053131541 in words is "one hundred one billion, fifty-three million, one hundred thirty-one thousand, five hundred forty-one".