101100121101011 has 2 divisors, whose sum is σ = 101100121101012. Its totient is φ = 101100121101010.

The previous prime is 101100121100863. The next prime is 101100121101013. The reversal of 101100121101011 is 110101121001101.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (110101121001101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101100121101011 - 2¹⁰ = 101100121099987 is a prime.

Together with 101100121101013, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 101100121100983 and 101100121101001.

It is not a weakly prime, because it can be changed into another prime (101100121101013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50550060550505 + 50550060550506.

It is an arithmetic number, because the mean of its divisors is an integer number (50550060550506).

Almost surely, 2^{101100121101011} is an apocalyptic number.

101100121101011 is a deficient number, since it is larger than the sum of its proper divisors (1).

101100121101011 is an equidigital number, since it uses as much as digits as its factorization.

101100121101011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2, while the sum is 11.

Adding to 101100121101011 its reverse (110101121001101), we get a palindrome (211201242102112).

The spelling of 101100121101011 in words is "one hundred one trillion, one hundred billion, one hundred twenty-one million, one hundred one thousand, eleven".