101100121101013 has 2 divisors, whose sum is σ = 101100121101014. Its totient is φ = 101100121101012.

The previous prime is 101100121101011. The next prime is 101100121101041. The reversal of 101100121101013 is 310101121001101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 99959544092529 + 1140577008484 = 9997977^2 + 1067978^2 .

It is a cyclic number.

It is not a de Polignac number, because 101100121101013 - 2¹ = 101100121101011 is a prime.

Together with 101100121101011, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 101100121100984 and 101100121101002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101100121101011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50550060550506 + 50550060550507.

It is an arithmetic number, because the mean of its divisors is an integer number (50550060550507).

Almost surely, 2^{101100121101013} is an apocalyptic number.

It is an amenable number.

101100121101013 is a deficient number, since it is larger than the sum of its proper divisors (1).

101100121101013 is an equidigital number, since it uses as much as digits as its factorization.

101100121101013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 101100121101013 its reverse (310101121001101), we get a palindrome (411201242102114).

The spelling of 101100121101013 in words is "one hundred one trillion, one hundred billion, one hundred twenty-one million, one hundred one thousand, thirteen".