101100551 has 2 divisors, whose sum is σ = 101100552. Its totient is φ = 101100550.

The previous prime is 101100499. The next prime is 101100553. The reversal of 101100551 is 155001101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 101100551 - 2¹⁴ = 101084167 is a prime.

Together with 101100553, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101100553) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50550275 + 50550276.

It is an arithmetic number, because the mean of its divisors is an integer number (50550276).

Almost surely, 2^101100551 is an apocalyptic number.

101100551 is a deficient number, since it is larger than the sum of its proper divisors (1).

101100551 is an equidigital number, since it uses as much as digits as its factorization.

101100551 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25, while the sum is 14.

The square root of 101100551 is about 10054.8769758759. The cubic root of 101100551 is about 465.8554430754.

Adding to 101100551 its reverse (155001101), we get a palindrome (256101652).

The spelling of 101100551 in words is "one hundred one million, one hundred thousand, five hundred fifty-one".