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1011121212100 = 225219817165129
BaseRepresentation
bin11101011011010111000…
…01010100101011000100
310120122212202221112110111
432231223201110223010
5113031234012241400
62052300324402404
7133023345331636
oct16555341245304
93518782845414
101011121212100
1135a8a562317a
12143b66546404
137446b352a0c
1436d1d46aa56
151b47cc9a3ba
hexeb6b854ac4

1011121212100 has 72 divisors (see below), whose sum is σ = 2309931842400. Its totient is φ = 383108947200.

The previous prime is 1011121212089. The next prime is 1011121212109. The reversal of 1011121212100 is 12121211101.

It is a happy number.

1011121212100 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-4 number, since 4×10111212121004 (a number of 49 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (1011121212109) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 15492336 + ... + 15557464.

It is an arithmetic number, because the mean of its divisors is an integer number (32082386700).

Almost surely, 21011121212100 is an apocalyptic number.

1011121212100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1011121212100 is an abundant number, since it is smaller than the sum of its proper divisors (1298810630300).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1011121212100 is a wasteful number, since it uses less digits than its factorization.

1011121212100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 73333 (or 73326 counting only the distinct ones).

The product of its (nonzero) digits is 8, while the sum is 13.

Adding to 1011121212100 its reverse (12121211101), we get a palindrome (1023242423201).

Subtracting from 1011121212100 its reverse (12121211101), we obtain a palindrome (999000000999).

It can be divided in two parts, 1011121 and 212100, that added together give a palindrome (1223221).

The spelling of 1011121212100 in words is "one trillion, eleven billion, one hundred twenty-one million, two hundred twelve thousand, one hundred".

Divisors: 1 2 4 5 10 19 20 25 38 50 76 95 100 190 380 475 950 1900 8171 16342 32684 40855 65129 81710 130258 155249 163420 204275 260516 310498 325645 408550 620996 651290 776245 817100 1237451 1302580 1552490 1628225 2474902 3104980 3256450 3881225 4949804 6187255 6512900 7762450 12374510 15524900 24749020 30936275 61872550 123745100 532169059 1064338118 2128676236 2660845295 5321690590 10111212121 10643381180 13304226475 20222424242 26608452950 40444848484 50556060605 53216905900 101112121210 202224242420 252780303025 505560606050 1011121212100