Base | Representation |
---|---|
bin | 1001001100100011001100… |
… | …1101100100111111011111 |
3 | 1022210121210202121222201021 |
4 | 2103020303031210333133 |
5 | 2311130230311242231 |
6 | 33301005440425011 |
7 | 2062340156505136 |
oct | 223106315447737 |
9 | 38717722558637 |
10 | 10111212212191 |
11 | 3249160771092 |
12 | 1173754618167 |
13 | 58463883433c |
14 | 26d55730091d |
15 | 128038689811 |
hex | 93233364fdf |
10111212212191 has 2 divisors, whose sum is σ = 10111212212192. Its totient is φ = 10111212212190.
The previous prime is 10111212212173. The next prime is 10111212212209. The reversal of 10111212212191 is 19121221211101.
It is a balanced prime because it is at equal distance from previous prime (10111212212173) and next prime (10111212212209).
It is a cyclic number.
It is not a de Polignac number, because 10111212212191 - 29 = 10111212211679 is a prime.
It is a super-2 number, since 2×101112122121912 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10111212212891) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055606106095 + 5055606106096.
It is an arithmetic number, because the mean of its divisors is an integer number (5055606106096).
Almost surely, 210111212212191 is an apocalyptic number.
10111212212191 is a deficient number, since it is larger than the sum of its proper divisors (1).
10111212212191 is an equidigital number, since it uses as much as digits as its factorization.
10111212212191 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 25.
Adding to 10111212212191 its reverse (19121221211101), we get a palindrome (29232433423292).
The spelling of 10111212212191 in words is "ten trillion, one hundred eleven billion, two hundred twelve million, two hundred twelve thousand, one hundred ninety-one".
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