101113020 has 72 divisors (see below), whose sum is σ = 311940720. Its totient is φ = 26503680.

The previous prime is 101113009. The next prime is 101113021. The reversal of 101113020 is 20311101.

It is a Harshad number since it is a multiple of its sum of digits (9).

It is a junction number, because it is equal to n+sod(n) for n = 101112993 and 101113011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101113021) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 5860 + ... + 15380.

It is an arithmetic number, because the mean of its divisors is an integer number (4332510).

Almost surely, 2^101113020 is an apocalyptic number.

101113020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 101113020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (155970360).

101113020 is an abundant number, since it is smaller than the sum of its proper divisors (210827700).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

101113020 is a wasteful number, since it uses less digits than its factorization.

101113020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9595 (or 9590 counting only the distinct ones).

The product of its (nonzero) digits is 6, while the sum is 9.

The square root of 101113020 is about 10055.4970041266. The cubic root of 101113020 is about 465.8745940186.

Adding to 101113020 its reverse (20311101), we get a palindrome (121424121).

It can be divided in two parts, 10111 and 3020, that added together give a palindrome (13131).

The spelling of 101113020 in words is "one hundred one million, one hundred thirteen thousand, twenty".