101113330100119 has 2 divisors, whose sum is σ = 101113330100120. Its totient is φ = 101113330100118.

The previous prime is 101113330100117. The next prime is 101113330100137. The reversal of 101113330100119 is 911001033311101.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 101113330100119 - 2¹ = 101113330100117 is a prime.

It is a super-2 number, since 2×101113330100119² (a number of 29 digits) contains 22 as substring.

Together with 101113330100117, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 101113330100093 and 101113330100102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101113330100117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50556665050059 + 50556665050060.

It is an arithmetic number, because the mean of its divisors is an integer number (50556665050060).

Almost surely, 2^{101113330100119} is an apocalyptic number.

101113330100119 is a deficient number, since it is larger than the sum of its proper divisors (1).

101113330100119 is an equidigital number, since it uses as much as digits as its factorization.

101113330100119 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 243, while the sum is 25.

The spelling of 101113330100119 in words is "one hundred one trillion, one hundred thirteen billion, three hundred thirty million, one hundred thousand, one hundred nineteen".