10111502130000 has 400 divisors, whose sum is σ = 33518992938816. Its totient is φ = 2624808960000.

The previous prime is 10111502129969. The next prime is 10111502130019. The reversal of 10111502130000 is 3120511101.

It is a tau number, because it is divible by the number of its divisors (400).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 177481519 + ... + 177538481.

Almost surely, 2^{10111502130000} is an apocalyptic number.

10111502130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 10111502130000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16759496469408).

10111502130000 is an abundant number, since it is smaller than the sum of its proper divisors (23407490808816).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10111502130000 is an equidigital number, since it uses as much as digits as its factorization.

10111502130000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 57152 (or 57131 counting only the distinct ones).

The product of its (nonzero) digits is 30, while the sum is 15.

Adding to 10111502130000 its reverse (3120511101), we get a palindrome (10114622641101).

The spelling of 10111502130000 in words is "ten trillion, one hundred eleven billion, five hundred two million, one hundred thirty thousand".