101121002110127 has 2 divisors, whose sum is σ = 101121002110128. Its totient is φ = 101121002110126.

The previous prime is 101121002110097. The next prime is 101121002110129. The reversal of 101121002110127 is 721011200121101.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 101121002110127 - 2¹⁶ = 101121002044591 is a prime.

It is a super-2 number, since 2×101121002110127² (a number of 29 digits) contains 22 as substring.

Together with 101121002110129, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 101121002110099 and 101121002110108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101121002110129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50560501055063 + 50560501055064.

It is an arithmetic number, because the mean of its divisors is an integer number (50560501055064).

Almost surely, 2^{101121002110127} is an apocalyptic number.

101121002110127 is a deficient number, since it is larger than the sum of its proper divisors (1).

101121002110127 is an equidigital number, since it uses as much as digits as its factorization.

101121002110127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 56, while the sum is 20.

Adding to 101121002110127 its reverse (721011200121101), we get a palindrome (822132202231228).

The spelling of 101121002110127 in words is "one hundred one trillion, one hundred twenty-one billion, two million, one hundred ten thousand, one hundred twenty-seven".