101122201120120 has 64 divisors (see below), whose sum is σ = 231411152304000. Its totient is φ = 39762472209408.

The previous prime is 101122201120117. The next prime is 101122201120133. The reversal of 101122201120120 is 21021102221101.

It is a super-3 number, since 3×101122201120120³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 101122201120094 and 101122201120103.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 69146877 + ... + 70594156.

It is an arithmetic number, because the mean of its divisors is an integer number (3615799254750).

Almost surely, 2^{101122201120120} is an apocalyptic number.

101122201120120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

101122201120120 is an abundant number, since it is smaller than the sum of its proper divisors (130288951183880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

101122201120120 is a wasteful number, since it uses less digits than its factorization.

101122201120120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 139741352 (or 139741348 counting only the distinct ones).

The product of its (nonzero) digits is 32, while the sum is 16.

Adding to 101122201120120 its reverse (21021102221101), we get a palindrome (122143303341221).

The spelling of 101122201120120 in words is "one hundred one trillion, one hundred twenty-two billion, two hundred one million, one hundred twenty thousand, one hundred twenty".