101130012 has 72 divisors (see below), whose sum is σ = 267699600. Its totient is φ = 33015456.

The previous prime is 101129999. The next prime is 101130017. The reversal of 101130012 is 210031101.

It is a Harshad number since it is a multiple of its sum of digits (9).

It is a zygodrome in base 2.

It is a junction number, because it is equal to n+sod(n) for n = 101129976 and 101130003.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101130017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 375814 + ... + 376082.

It is an arithmetic number, because the mean of its divisors is an integer number (3718050).

Almost surely, 2^101130012 is an apocalyptic number.

101130012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 101130012, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (133849800).

101130012 is an abundant number, since it is smaller than the sum of its proper divisors (166569588).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

101130012 is a wasteful number, since it uses less digits than its factorization.

101130012 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 400 (or 333 counting only the distinct ones).

The product of its (nonzero) digits is 6, while the sum is 9.

The square root of 101130012 is about 10056.3418796300. The cubic root of 101130012 is about 465.9006892327.

Adding to 101130012 its reverse (210031101), we get a palindrome (311161113).

The spelling of 101130012 in words is "one hundred one million, one hundred thirty thousand, twelve".