10113013151 has 2 divisors, whose sum is σ = 10113013152. Its totient is φ = 10113013150.

The previous prime is 10113013121. The next prime is 10113013153. The reversal of 10113013151 is 15131031101.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10113013151 is a prime.

Together with 10113013153, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10113013153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056506575 + 5056506576.

It is an arithmetic number, because the mean of its divisors is an integer number (5056506576).

Almost surely, 2^10113013151 is an apocalyptic number.

10113013151 is a deficient number, since it is larger than the sum of its proper divisors (1).

10113013151 is an equidigital number, since it uses as much as digits as its factorization.

10113013151 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 45, while the sum is 17.

Adding to 10113013151 its reverse (15131031101), we get a palindrome (25244044252).

The spelling of 10113013151 in words is "ten billion, one hundred thirteen million, thirteen thousand, one hundred fifty-one".