Base | Representation |
---|---|
bin | 1001001100101010010001… |
… | …0110010000010010110000 |
3 | 1022210210201001020110022100 |
4 | 2103022210112100102300 |
5 | 2311143122214441422 |
6 | 33301522043340400 |
7 | 2062435205212143 |
oct | 223124426202260 |
9 | 38723631213270 |
10 | 10113110312112 |
11 | 3249a45139705 |
12 | 1173ba4221700 |
13 | 58487bb510a2 |
14 | 26d69743205a |
15 | 1280ea11e7ac |
hex | 932a45904b0 |
10113110312112 has 60 divisors (see below), whose sum is σ = 28303028845624. Its totient is φ = 3370993182720.
The previous prime is 10113110312099. The next prime is 10113110312131. The reversal of 10113110312112 is 21121301131101.
10113110312112 is a `hidden beast` number, since 101 + 131 + 10 + 312 + 112 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 11880912 + ... + 12703632.
Almost surely, 210113110312112 is an apocalyptic number.
10113110312112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
10113110312112 is an abundant number, since it is smaller than the sum of its proper divisors (18189918533512).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
10113110312112 is a wasteful number, since it uses less digits than its factorization.
10113110312112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 908098 (or 908089 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 18.
Adding to 10113110312112 its reverse (21121301131101), we get a palindrome (31234411443213).
The spelling of 10113110312112 in words is "ten trillion, one hundred thirteen billion, one hundred ten million, three hundred twelve thousand, one hundred twelve".
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