101134102021 has 2 divisors, whose sum is σ = 101134102022. Its totient is φ = 101134102020.

The previous prime is 101134102019. The next prime is 101134102037. The reversal of 101134102021 is 120201431101.

It is an a-pointer prime, because the next prime (101134102037) can be obtained adding 101134102021 to its sum of digits (16).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 98605420225 + 2528681796 = 314015^2 + 50286^2 .

It is an emirp because it is prime and its reverse (120201431101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101134102021 - 2¹ = 101134102019 is a prime.

Together with 101134102019, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 101134101986 and 101134102004.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101134102001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50567051010 + 50567051011.

It is an arithmetic number, because the mean of its divisors is an integer number (50567051011).

Almost surely, 2^101134102021 is an apocalyptic number.

It is an amenable number.

101134102021 is a deficient number, since it is larger than the sum of its proper divisors (1).

101134102021 is an equidigital number, since it uses as much as digits as its factorization.

101134102021 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 101134102021 its reverse (120201431101), we get a palindrome (221335533122).

The spelling of 101134102021 in words is "one hundred one billion, one hundred thirty-four million, one hundred two thousand, twenty-one".