Base | Representation |
---|---|
bin | 10111000000101010111000… |
… | …110100100101011101001111 |
3 | 111021022201210001220202121002 |
4 | 113000222320310211131033 |
5 | 101231034343234033012 |
6 | 555123053001330515 |
7 | 30213353046440612 |
oct | 2700527064453517 |
9 | 437281701822532 |
10 | 101201120221007 |
11 | 2a278177069954 |
12 | b425556496a3b |
13 | 44612bc841501 |
14 | 1adc236020179 |
15 | ba77179d77c2 |
hex | 5c0ab8d2574f |
101201120221007 has 2 divisors, whose sum is σ = 101201120221008. Its totient is φ = 101201120221006.
The previous prime is 101201120220913. The next prime is 101201120221147. The reversal of 101201120221007 is 700122021102101.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-101201120221007 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 101201120221007.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101201120227007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50600560110503 + 50600560110504.
It is an arithmetic number, because the mean of its divisors is an integer number (50600560110504).
Almost surely, 2101201120221007 is an apocalyptic number.
101201120221007 is a deficient number, since it is larger than the sum of its proper divisors (1).
101201120221007 is an equidigital number, since it uses as much as digits as its factorization.
101201120221007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 20.
Adding to 101201120221007 its reverse (700122021102101), we get a palindrome (801323141323108).
The spelling of 101201120221007 in words is "one hundred one trillion, two hundred one billion, one hundred twenty million, two hundred twenty-one thousand, seven".
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