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101201211220212 = 223329311811575551
BaseRepresentation
bin10111000000101010111110…
…001111101110000011110100
3111021022202000102011000001000
4113000222332033232003310
5101231040040033021322
6555123110012003300
730213355233064455
oct2700527617560364
9437282012130030
10101201211220212
112a278213472a04
12b425580a60530
1344613056531ac
141adc24414b12c
15ba77209b03ac
hex5c0abe3ee0f4

101201211220212 has 192 divisors, whose sum is σ = 280331580211200. Its totient is φ = 31502383920000.

The previous prime is 101201211220211. The next prime is 101201211220217. The reversal of 101201211220212 is 212022112102101.

101201211220212 is a `hidden beast` number, since 1 + 0 + 1 + 20 + 1 + 211 + 220 + 212 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101201211220211) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 175545837 + ... + 176121387.

It is an arithmetic number, because the mean of its divisors is an integer number (1460060313600).

Almost surely, 2101201211220212 is an apocalyptic number.

101201211220212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 101201211220212, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (140165790105600).

101201211220212 is an abundant number, since it is smaller than the sum of its proper divisors (179130368990988).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

101201211220212 is a wasteful number, since it uses less digits than its factorization.

101201211220212 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 577435 (or 577427 counting only the distinct ones).

The product of its (nonzero) digits is 64, while the sum is 18.

Adding to 101201211220212 its reverse (212022112102101), we get a palindrome (313223323322313).

The spelling of 101201211220212 in words is "one hundred one trillion, two hundred one billion, two hundred eleven million, two hundred twenty thousand, two hundred twelve".