Base | Representation |
---|---|
bin | 111100010100100… |
… | …001010011000111 |
3 | 2121112021112210111 |
4 | 330110201103013 |
5 | 4033033342411 |
6 | 244230533451 |
7 | 34035650656 |
oct | 7424412307 |
9 | 2545245714 |
10 | 1012012231 |
11 | 47a28884a |
12 | 242b07287 |
13 | 131884909 |
14 | 9859719d |
15 | 5dca5721 |
hex | 3c5214c7 |
1012012231 has 2 divisors, whose sum is σ = 1012012232. Its totient is φ = 1012012230.
The previous prime is 1012012229. The next prime is 1012012247. The reversal of 1012012231 is 1322102101.
It is a weak prime.
It is an emirp because it is prime and its reverse (1322102101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1012012231 - 21 = 1012012229 is a prime.
It is a super-2 number, since 2×10120122312 = 2048337511387194722, which contains 22 as substring.
Together with 1012012229, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1012012201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506006115 + 506006116.
It is an arithmetic number, because the mean of its divisors is an integer number (506006116).
Almost surely, 21012012231 is an apocalyptic number.
1012012231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1012012231 is an equidigital number, since it uses as much as digits as its factorization.
1012012231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 13.
The square root of 1012012231 is about 31812.1396796883. The cubic root of 1012012231 is about 1003.9881505112.
Adding to 1012012231 its reverse (1322102101), we get a palindrome (2334114332).
The spelling of 1012012231 in words is "one billion, twelve million, twelve thousand, two hundred thirty-one".
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