101202120221 has 2 divisors, whose sum is σ = 101202120222. Its totient is φ = 101202120220.

The previous prime is 101202120193. The next prime is 101202120223. The reversal of 101202120221 is 122021202101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 82777044100 + 18425076121 = 287710^2 + 135739^2 .

It is an emirp because it is prime and its reverse (122021202101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101202120221 - 2⁶ = 101202120157 is a prime.

Together with 101202120223, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 101202120196 and 101202120205.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101202120223) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50601060110 + 50601060111.

It is an arithmetic number, because the mean of its divisors is an integer number (50601060111).

Almost surely, 2^101202120221 is an apocalyptic number.

It is an amenable number.

101202120221 is a deficient number, since it is larger than the sum of its proper divisors (1).

101202120221 is an equidigital number, since it uses as much as digits as its factorization.

101202120221 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32, while the sum is 14.

Adding to 101202120221 its reverse (122021202101), we get a palindrome (223223322322).

The spelling of 101202120221 in words is "one hundred one billion, two hundred two million, one hundred twenty thousand, two hundred twenty-one".